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Proof step 9 from proof subarray-copy (previous step)

n < # mkarray(m1), m0 + m1 ≤ # ar1, n < m1 ⊦ (n < 0 ∨ 0 + m1 ≤ n ⊃ mkarray(m1)[n];copy(ar0, n0, ar1, n3 + m0, n2)[n + m0 - 0]) = copy(ar0, n0, copy(ar1, m0, mkarray(m1), 0, m1), n3, n2)[n], m1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
m0 + m1 ≤ # ar1, n < m1 ⊦ m1 = 0, copy(ar0, n0, ar1, n3 + m0, n2)[n + m0] = copy(ar0, n0, copy(ar1, m0, mkarray(m1), 0, m1), n3, n2)[n]

Rule argument

Additional information

Used simplifier rules: Size-mkarray: ⊦ # mkarray(n) = n; from specification array%sub-base: ⊦ m - 0 = m; from specification nat%ls-le-simp: ⊦ m < n → (n ≤ m ↔ false); from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%add-base: ⊦ n + 0 = n; from specification nat-basic2%zero-01: ⊦ ¬ m < 0; from specification nat-basic1