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Proof step 1 from proof subarray-up-same (conclusion)

⊦ n < # ar → subarray(ar[n, a], 0, n) = subarray(ar, 0, n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n < # ar ⊦ copy(ar[n, a], 0, mkarray(n), 0, n) = copy(ar, 0, mkarray(n), 0, n), # ar = 0

Rule argument

Additional information

Used simplifier rules: Subarray: ⊦ subarray(ar, m, n) = copy(ar, m, mkarray(n), 0, n);%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1