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Proof step 2 from proof subarray-write-below (previous step)

n < n0 ⊦ copy(ar[n, a], n0, mkarray(n1), 0, n1) = copy(ar, n0, mkarray(n1), 0, n1), n0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n])
Proof step 4:
n < n0 ⊦ # copy(ar[n, a], n0, mkarray(n1), 0, n1) = # copy(ar, n0, mkarray(n1), 0, n1) ∧ (∀ n2. n2 < # copy(ar[n, a], n0, mkarray(n1), 0, n1) → copy(ar[n, a], n0, mkarray(n1), 0, n1)[n2] = copy(ar, n0, mkarray(n1), 0, n1)[n2]), n0 = 0

Rule argument

spec: array inst: name: Extension seq: ⊦ ar1 = ar2 ↔ # ar1 = # ar2 ∧ (∀ n. n < # ar1 → ar1[n] = ar2[n]) subst: [ar2, ar1] → [copy(ar, n0, mkarray(n1), 0, n1), copy(ar[n, a], n0, mkarray(n1), 0, n1)] flags: rewrite

Additional information

Used terms: copy(ar, n0, mkarray(n1), 0, n1), copy(ar[n, a], n0, mkarray(n1), 0, n1)