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Proof step 12 from proof ext-rec (previous step)

# ar0 = # ar1, n < # ar1, ∀ m. m < # ar1 → ar1[m] = (n = m ⊃ a;ar0[m]) ⊦ ar1[n] = a, # ar1 = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n

Additional information

Used terms: n