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Proof step 13 from proof ext-rec (previous step)

n0 ≠ n, # ar0 = # ar1, n0 < # ar1, ∀ m. m < # ar1 → ar1[m] = (n = m ⊃ a;ar0[m]) ⊦ # ar1 = 0, ar1[n0] = ar0[n0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information