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Proof step 3 from proof ext-rec (previous step)

m < # ar0 ⊦ ar0[n, a][m] = (n = m ⊃ a;ar0[m]), # ar0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ m ≠ n → ar[n, a][m] = ar[m]

Rule argument

spec: inst: name: Put-other seq: ⊦ m ≠ n → ar[n, a][m] = ar[m] subst: [m, a, n, ar] → [m, a, n, ar0] flags: rewrite, current

Additional information

Used simplifier rules: Put-same: ⊦ m < # ar → ar[m, a][m] = a; Used terms: m, a, n, ar0