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Proof step 5 from proof put-both-eq (previous step)

n < # ar, ∀ n0. n0 < # ar → ar[n, a][n0] = ar[n, b][n0] ⊦ a = b, # ar = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: n

Additional information

Used simplifier rules: Put-same: ⊦ m < # ar → ar[m, a][m] = a; Used terms: n