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Proof step 1 from proof app (conclusion)

⊦ unique_al(ax + p ' + ay) → unique_al(ax + ay)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
unique_al(ax + p ' + ay) ⊦ ax + ay = [], ¬ (ax + ay).first.1 ∈ (ax + ay).rest ∧ unique_al((ax + ay).rest)

Rule argument

Additional information

Used simplifier rules: k-unique-r: ⊦ unique_al(ay) ↔ ay = [] ∨ ¬ ay.first.1 ∈ ay.rest ∧ unique_al(ay.rest);