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Proof step 8 from proof in-put (previous step)

∀ a, b, d. a ∈ ax0[b, d] ↔ a = b ∨ a ∈ ax0 ⊦ b = a0, a ∈ ax0[b, d] ↔ a = b ∨ a ∈ ax0, a = a0

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: a, b, d abort: F discard: F computed: T

Additional information

Used terms: a, b, d