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Proof step 6 from proof insnotin (previous step)

∀ a, d. ax0[a, d] = ax0 + (a × d)' ∨ a ∈ ax0 ⊦ a = a0, ax0[a, d] = ax0 + (a × d)', a ∈ ax0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: a, d

Additional information

Used terms: a, d