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Proof step 15 from proof lenle (
previous step
)
# ay0 + # az < # ax0, unique_al(ax0.rest), a0 ∈ ax0, ∀ a0. a0 ∈ ax0 → a0 ∈ ay0 ∨ a0 ∈ az ⊦ ax0 = [], ax0.first.1 ∈ ax0.rest, a ∈ ax0, a0 ∈ ay0, a0 ∈ az
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 4 terms: a0
Additional information
Used terms: a0