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Proof step 9 from proof lenle (previous step)

# ay ≤ # ax0, unique_al(ax0.rest), a = a ∨ a ∈ ax0 → a ∈ ay, ∀ a0. a0 ∈ ax0 → a0 ∈ ay ⊦ ax0 = [], a ∈ ax0, ax0.first.1 ∈ ax0.rest, ∃ ay0. # ay0 < # ax0 ∧ (∀ a. a ∈ ax0 → a ∈ ay0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
# ay ≤ # ax0, unique_al(ax0.rest), a ∈ ay, ∀ a0. a0 ∈ ax0 → a0 ∈ ay ⊦ ax0 = [], a ∈ ax0, ax0.first.1 ∈ ax0.rest, ∃ ay0. # ay0 < # ax0 ∧ (∀ a. a ∈ ax0 → a ∈ ay0)

Proof step 9 from proof lenle (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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