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Proof step 6 from proof nuni (previous step)

unique_al(ay0 + (a × d)' + az), a ∈ ay0, ∀ a, d, az. a ∈ ay0 ∧ unique_al(ay0 + (a × d)' + az) → a ∈ az ⊦ a ∈ az, a0 ∈ az, a0 ∈ ay0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a, d, az

Additional information

Used simplifier rules: a: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; from specification list[assoclista] Used terms: a, d, az