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Proof step 1 from proof unique-02 (conclusion)
⊦ unique_al(ax) ∧ a × d ∈ ax ∧ a × d0 ∈ ax → d = d0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
unique_al(ax), a × d ∈ ax, a × d0 ∈ ax ⊦ d = d0
Rule argument
Additional information