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Proof step 8 from proof unique-02 (
previous step
)
a × d0 ∈ ax0, a × d ∈ ax0, unique_al(ax0), ∀ a1, d2, d3. a1 × d2 ∈ ax0 ∧ a1 × d3 ∈ ax0 → d2 = d3 ⊦ d = d0, a0 ∈ ax0
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 4 terms: a, d0, d
Additional information
Used terms: a, d0, d