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Proof step 1 from proof insert-inj (conclusion)

⊦ bag0 ++ a = bag1 ++ a ↔ bag0 = bag1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bag0 ++ a = bag1 ++ a ⊦ bag0 = bag1

Rule argument

Additional information