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Proof step 4 from proof insert-inj (previous step)

bag0 ++ a = bag1 ++ a ⊦ ∀ a. count(a, bag0) = count(a, bag1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
bag0 ++ a = bag1 ++ a ⊦ count(a0, bag0) = count(a0, bag1)

Rule argument

Additional information