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Proof step 1 from proof difference (conclusion)

⊦ count(a, bag0 \ bag1) = (count(a, bag1) ≤ count(a, bag0) ⊃ count(a, bag0) - count(a, bag1);0)

User applied rule cut formula

And obtained the following new goals

Proof step 2:
count(a, bag0 \ bag1) = (count(a, bag1) < count(a, bag0) ⊃ count(a, bag0) - count(a, bag1);0) ⊦ count(a, bag0 \ bag1) = (count(a, bag1) ≤ count(a, bag0) ⊃ count(a, bag0) - count(a, bag1);0)
Proof step 3:
⊦ count(a, bag0 \ bag1) = (count(a, bag1) < count(a, bag0) ⊃ count(a, bag0) - count(a, bag1);0), count(a, bag0 \ bag1) = (count(a, bag1) ≤ count(a, bag0) ⊃ count(a, bag0) - count(a, bag1);0)

Rule argument

fma: count(a, bag0 \ bag1) = (count(a, bag1) < count(a, bag0) ⊃ count(a, bag0) - count(a, bag1) ;0 )

Additional information

Used formulas: count(a, bag0 \ bag1) = (count(a, bag1) < count(a, bag0) ⊃ count(a, bag0) - count(a, bag1) ;0 )