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Proof step 9 from proof subset-antisym (previous step)

∀ a. count(a, bag1) ≤ count(a, bag0), ∀ a. count(a, bag0) ≤ count(a, bag1) ⊦ count(a, bag0) = count(a, bag1)

User applied rule all left

And obtained the following new goals

Proof step 10:
∀ a. count(a, bag1) ≤ count(a, bag0), count(a, bag0) ≤ count(a, bag1), ∀ a. count(a, bag0) ≤ count(a, bag1) ⊦ count(a, bag0) = count(a, bag1)

Rule argument

pos: left 2 terms: a abort: F discard: F computed: T

Additional information

Used terms: a