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Proof step 7 from proof subset-plusplus (previous step)

count(a0, bag1) < count(a0, bag0), ∀ a0. count(a0, bag0 ++ a) ≤ count(a0, bag1 ++ a) ⊦ count(a0, bag0) = 0

User applied rule all left

And obtained the following new goals

Proof step 8:
count(a0, bag1) < count(a0, bag0), count(a0, bag0 ++ a) ≤ count(a0, bag1 ++ a), ∀ a0. count(a0, bag0 ++ a) ≤ count(a0, bag1 ++ a) ⊦ count(a0, bag0) = 0

Rule argument

pos: left 2 terms: a0 abort: F discard: F computed: F

Additional information

Used terms: a0