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Proof step 7 from proof subset-smaller (previous step)

count(a0, bag ++ a) < count(a0, bag0), ∀ a. count(a, bag0) ≤ count(a, bag) ⊦ count(a0, bag0) = 0

User applied rule all left

And obtained the following new goals

Proof step 8:
count(a0, bag ++ a) < count(a0, bag0), count(a0, bag0) ≤ count(a0, bag), ∀ a. count(a, bag0) ≤ count(a, bag) ⊦ count(a0, bag0) = 0

Rule argument

pos: left 2 terms: a0 abort: F discard: F computed: F

Additional information

Used terms: a0