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Proof step 3 from proof induction-hol (previous step)

∀ x. μ(f)(x) → φ(x), monotone(f), μ(f)(x), ∀ x. f(λ x. μ(f)(x) ∧ φ(x))(x) → φ(x) ⊦ φ(x)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: x

Additional information

Used terms: x