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Proof step 85 from proof infinite-append-prefixnextli (previous step)

ii(m + 1) = ii(m), nextli(lf(n)) = lf(n), # lf(n) = ii(n), lf(0) = [], ii(0) = 0, ii(n + 1) = ii(n), nextli0(lf(n)) = [], ii(n0) = ii(n), nextli0(lf(n0)) = [], m < n0, n ≤ n0, ∀ n. nextli0(lf(n)) = [] → (∀ m. n < m → lf(m) = lf(n) ∧ nextli0(lf(m)) = [] ∧ ii(m) = ii(n)), ∀ m. nextli0(lf(m)) = [] ↔ n0 ≤ m, ii(m + 1) = ii(m) + # nextli0(lf(m)) ∧ ¬ ii(n) < ii(m + 1) ∧ (lf(n) from ii(m)) to # nextli0(lf(m)) = nextli0(lf(m)), ∀ n0. ii(n0 + 1) = ii(n0) + # nextli0(lf(n0)) ∧ ¬ ii(n) < ii(n0 + 1) ∧ (lf(n) from ii(n0)) to # nextli0(lf(n0)) = nextli0(lf(n0)), ∀ n0. lf(n0) = lf(n) to ii(n0), ∀ m. n ≤ m → nextli0(lf(m)) = [] ∧ ii(m) = ii(n), ∀ x. nextli(x) = x + nextli0(x), ∀ n. lf(n + 1) = nextli(lf(n)), ∀ m, n. m ≤ n → ii(m) ≤ ii(n) ⊦ n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: to-zero-l: ⊦ x to 0 = []; from specification stream%size-01: ⊦ # [] = 0; from specification list-data%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%l: ⊦ # x = 0 ↔ x = []; from specification list-data%eq: ⊦ m = m + n ↔ n = 0; from specification nat-basic2%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat