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Proof step 2 from proof nextli-lemma (previous step)

∀ n. ∃ lf. lf(0) = [] ∧ (∀ m. m < n → lf(m + 1) = nextli(lf(m))) ⊦ ∃ lf. lf(0) = [] ∧ (∀ n. lf(n + 1) = nextli(lf(n)))

User applied rule choice left

And obtained the following new goals

Proof step 3:
∀ n. lfgen(n)(0) = [] ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextli(lfgen(n)(m))) ⊦ ∃ lf. lf(0) = [] ∧ (∀ n. lf(n + 1) = nextli(lf(n)))

Rule argument

pos: left 1

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