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Proof step 38 from proof nextli-lemma (previous step)

lf(0) = [], ∀ m. m < n0 → lf(m + 1) = nextli(lf(m)) ⊦ ∃ lf. lf(0) = [] ∧ (∀ m. ¬ n0 < m → lf(m + 1) = nextli(lf(m)))

User applied rule exists right

And obtained the following new goals

Proof step 39:
lf(0) = [], ∀ m. m < n0 → lf(m + 1) = nextli(lf(m)) ⊦ (0 = n0 + 1 ⊃ nextli(lf(n0));lf(0)) = [] ∧ (∀ m. ¬ n0 < m → (m + 1 = n0 + 1 ⊃ nextli(lf(n0));lf(m + 1)) = nextli((m = n0 + 1 ⊃ nextli(lf(n0));lf(m))))

Rule argument

pos: right 1 terms: λ n. (n = n0 + 1 ⊃ nextli(lf(n0));lf(n)) abort: F discard: T computed: F

Additional information

Used terms: λ n. (n = n0 + 1 ⊃ nextli(lf(n0));lf(n))