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Proof step 2 from proof nextnli-lemma (previous step)

∀ n. ∃ lf. lf(0) = x ∧ (∀ m. m < n → lf(m + 1) = nextnli(lf(m), m)) ⊦ ∃ lf. lf(0) = x ∧ (∀ n. lf(n + 1) = nextnli(lf(n), n))

User applied rule choice left

And obtained the following new goals

Proof step 3:
∀ n. lfgen(n)(0) = x ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextnli(lfgen(n)(m), m)) ⊦ ∃ lf. lf(0) = x ∧ (∀ n. lf(n + 1) = nextnli(lf(n), n))

Rule argument

pos: left 1

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