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Proof step 36 from proof nextnli-lemma (previous step)

∀ x, nextnli. ∃ lf. lf(0) = x ∧ (∀ m. m < n0 → lf(m + 1) = nextnli(lf(m), m)) ⊦ ∃ lf. lf(0) = x ∧ (∀ m. m < n0 +1 → lf(m + 1) = nextnli(lf(m), m))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 37:
∀ x, nextnli. ∃ lf. lf(0) = x ∧ (∀ m. m < n0 → lf(m + 1) = nextnli(lf(m), m)) ⊦ ∃ lf. lf(0) = x ∧ (∀ m. ¬ n0 < m → lf(m + 1) = nextnli(lf(m), m))

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2%succ: ⊦ m +1 = m + 1; from specification nat-basic2