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Proof step 65 from proof infinite-append-butlast (previous step)

ii(m) = 0, ii(n0 + 1) = ii(n0) + # (n0 = 0 ⊃ lf(0);lf(n0).rest), ii(n0 + 1) = ((n0 = 0 ⊃ 0;ii(n0) - 1) + # lf(n0) - 1) + 1, ii(0) = 0, (nf from ii(n0)) to # (n0 = 0 ⊃ lf(0);lf(n0).rest) = (n0 = 0 ⊃ lf(0);lf(n0).rest), n2 < 0 - 1, n2 + 1 < ii(m + 1), ∀ n. n ≠ 0 → ii(n) ≠ 0, ∀ m, n. m ≤ n → ii(m) ≤ ii(n), ∀ n. lf(n).last = lf(n + 1).first ∧ lf(n) ≠ [], ∀ n. nf(ii(n + 1) - 1) = lf(n + 1).first, ∀ n. ii(n + 1) = ii(n) + # (n = 0 ⊃ lf(0);lf(n).rest) ∧ (nf from ii(n)) to # (n = 0 ⊃ lf(0);lf(n).rest) = (n = 0 ⊃ lf(0);lf(n).rest) ⊦ m = 0, 0 = 0 - 1, ii(m + 1) = 0

Proof step 65 from proof infinite-append-butlast (previous step)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

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