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Proof step 41 from proof infinite-append-lem (previous step)

ii(m) + n = n1 + ii(n0), ii(0) = 0, ii(m + 1) = ii(m) + # lf(m), (nf from ii(m)) to # lf(m) = lf(m), m < n0, n < # lf(m), n1 < # lf(n0), n0 - 1 < n0 → ii((n0 - 1) + 1) = ii(n0 - 1) + # lf(n0 - 1) ∧ (nf from ii(n0 - 1)) to # lf(n0 - 1) = lf(n0 - 1) ∧ (∀ m0. m0 ≤ n0 - 1 → ii(m0) ≤ ii(n0 - 1)), ∀ m. m < n0 → ii(m + 1) = ii(m) + # lf(m) ∧ (nf from ii(m)) to # lf(m) = lf(m) ∧ (∀ m0. m0 ≤ m → ii(m0) ≤ ii(m)), ∀ m0. m0 ≤ m → ii(m0) ≤ ii(m) ⊦ ii(n0) + # lf(n0) = 0, lf(m) = [], m = n0 + 1, n0 = m, n0 = 0, lf(n0)[n1] = lf(m)[n], lf(n0) = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 42:
ii(m) + n = n1 + ii(n0), ii(0) = 0, ii(m + 1) = ii(m) + # lf(m), (nf from ii(m)) to # lf(m) = lf(m), ii((n0 - 1) + 1) = ii(n0 - 1) + # lf(n0 - 1), (nf from ii(n0 - 1)) to # lf(n0 - 1) = lf(n0 - 1), m < n0, n < # lf(m), n1 < # lf(n0), ∀ m. m < n0 → ii(m + 1) = ii(m) + # lf(m) ∧ (nf from ii(m)) to # lf(m) = lf(m) ∧ (∀ m0. m0 ≤ m → ii(m0) ≤ ii(m)), ∀ m0. m0 ≤ m → ii(m0) ≤ ii(m), ∀ m0. m0 < n0 → ii(m0) ≤ ii(n0 - 1) ⊦ ii(n0) + # lf(n0) = 0, lf(m) = [], m = n0 + 1, n0 = m, n0 = 0, lf(n0)[n1] = lf(m)[n], lf(n0) = []

Rule argument

Additional information

Used simplifier rules: succ-01: ⊦ m + 1 ≤ n ↔ m < n; from specification nat%ls-02: n0 ≤ n ⊦ m ≤ n - n0 ↔ m + n0 ≤ n; from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%ref-1: ⊦ ¬ n < n; from specification nat-basic1%s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2%ls-01: n0 ≤ n ⊦ n - n0 < m ↔ n < m + n0; from specification nat%one-01: ⊦ m < 1 ↔ m = 0; from specification nat-basic1%lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat