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Proof step 14 from proof nextl-lemma-butlast-nonempty (previous step)

lfgen(0)(0) = a ', lfgen(n)(n) = lfgen(n + 1)(n), lfgen(n + 1)(0) = a ', ∀ m, n1, n2. m ≤ n1 ∧ n1 ≤ n2 → lfgen(n1)(m) = lfgen(n2)(m), ∀ n. lfgen(n)(0) = a ' ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextl(m, lfgen(n)(m).last) ∧ lfgen(n)(m) ≠ []), ∀ n, a. nextl(n, a) ≠ [], ∀ m. ¬ n < m → lfgen(n + 1)(m + 1) = nextl(m, lfgen(n + 1)(m).last) ∧ lfgen(n + 1)(m) ≠ [] ⊦ lfgen(n + 1)(n + 1) = nextl(n, lfgen(n)(n).last) ∧ lfgen(n)(n) ≠ []

User applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: n abort: F discard: F computed: T

Additional information

Used simplifier rules: ref-1: ⊦ ¬ n < n; from specification nat-basic1 Used terms: n