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Proof step 20 from proof nextl-lemma-butlast-nonempty (previous step)

lfgen(0)(0) = a ', n1 ≤ n0, lfgen(n0)(0) = a ' ∧ (∀ m. m < n0 → lfgen(n0)(m + 1) = nextl(m, lfgen(n0)(m).last) ∧ lfgen(n0)(m) ≠ []), ∀ n. lfgen(n)(0) = a ' ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextl(m, lfgen(n)(m).last) ∧ lfgen(n)(m) ≠ []), ∀ n, a. nextl(n, a) ≠ [] ⊦ lfgen(n1)(0) = lfgen(n0)(0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
lfgen(0)(0) = a ', lfgen(n0)(0) = a ', n1 ≤ n0, ∀ m. m < n0 → lfgen(n0)(m + 1) = nextl(m, lfgen(n0)(m).last) ∧ lfgen(n0)(m) ≠ [], ∀ n. lfgen(n)(0) = a ' ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextl(m, lfgen(n)(m).last) ∧ lfgen(n)(m) ≠ []), ∀ n, a. nextl(n, a) ≠ [] ⊦ lfgen(n1)(0) = a '

Proof step 20 from proof nextl-lemma-butlast-nonempty (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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