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Proof step 38 from proof nextl-lemma-butlast-nonempty (previous step)

∀ nextl, a. (∀ n, a. nextl(n, a) ≠ []) → (∃ lf. lf(0) = a ' ∧ (∀ m. m < n0 → lf(m + 1) = nextl(m, lf(m).last) ∧ lf(m) ≠ [])), ∀ n, a. nextl(n, a) ≠ [] ⊦ ∃ lf. lf(0) = a ' ∧ (∀ m. ¬ n0 < m → lf(m + 1) = nextl(m, lf(m).last) ∧ lf(m) ≠ [])

User applied rule all left

And obtained the following new goals

Proof step 39:
(∀ n, a. nextl(n, a) ≠ []) → (∃ lf. lf(0) = a ' ∧ (∀ m. m < n0 → lf(m + 1) = nextl(m, lf(m).last) ∧ lf(m) ≠ [])), ∀ n, a. nextl(n, a) ≠ [] ⊦ ∃ lf. lf(0) = a ' ∧ (∀ m. ¬ n0 < m → lf(m + 1) = nextl(m, lf(m).last) ∧ lf(m) ≠ [])

Rule argument

pos: left 1 terms: nextl, a abort: F discard: T computed: T

Additional information

Used terms: nextl, a