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Proof step 51 from proof nextl-lemma-butlast-nonempty (previous step)

lf(m) = [], lf(0) = a ', m ≤ n0, ∀ n, a. nextl(n, a) ≠ [], ∀ m. m < n0 → lf(m + 1) = nextl(m, lf(m).last) ∧ lf(m) ≠ [] ⊦ m = n0 + 1

User applied rule all left

And obtained the following new goals

Proof step 52:
lf(m) = [], lf(0) = a ', m ≤ n0, ∀ n, a. nextl(n, a) ≠ [], m - 1 < n0 → lf((m - 1) + 1) = nextl(m - 1, lf(m - 1).last) ∧ lf(m - 1) ≠ [] ⊦ m = n0 + 1

Rule argument

pos: left 5 terms: m - 1 abort: F discard: T computed: F

Additional information

Used terms: m - 1