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Proof step 19 from proof nextl-lemma-butlast (previous step)

lfgen(0)(0) = a ', n1 ≤ n0, ∀ n. lfgen(n)(0) = a ' ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextl(m, lfgen(n)(m).last)) ⊦ lfgen(n1)(0) = lfgen(n0)(0)

User applied rule all left

And obtained the following new goals

Proof step 20:
lfgen(0)(0) = a ', n1 ≤ n0, lfgen(n0)(0) = a ' ∧ (∀ m. m < n0 → lfgen(n0)(m + 1) = nextl(m, lfgen(n0)(m).last)), ∀ n. lfgen(n)(0) = a ' ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextl(m, lfgen(n)(m).last)) ⊦ lfgen(n1)(0) = lfgen(n0)(0)

Rule argument

pos: left 3 terms: n0 abort: F discard: F computed: T

Additional information

Used terms: n0