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Proof step 21 from proof nextl-lemma-butlast (previous step)

lfgen(0)(0) = a ', lfgen(n0)(0) = a ', n1 ≤ n0, ∀ m. m < n0 → lfgen(n0)(m + 1) = nextl(m, lfgen(n0)(m).last), ∀ n. lfgen(n)(0) = a ' ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextl(m, lfgen(n)(m).last)) ⊦ lfgen(n1)(0) = a '

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n1

Additional information

Used terms: n1