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Proof step 35 from proof nextl-lemma (
previous step
)
⊦ ∃ lf. lf(0) = nextl(0, a) ∧ (∀ m. m < 0 → lf(m + 1) = nextl(m + 1, lf(m).last))
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 36
:
⊦ ∃ lf. lf(0) = nextl(0, a)
Rule argument
Additional information
Used simplifier rules: zero-01: ⊦ ¬ m < 0; from specification nat-basic1