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Proof step 37 from proof nextl-lemma (previous step)

∀ nextl, a. ∃ lf. lf(0) = nextl(0, a) ∧ (∀ m. m < n0 → lf(m + 1) = nextl(m + 1, lf(m).last)) ⊦ ∃ lf. lf(0) = nextl(0, a) ∧ (∀ m. m < n0 +1 → lf(m + 1) = nextl(m + 1, lf(m).last))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
∀ nextl, a. ∃ lf. lf(0) = nextl(0, a) ∧ (∀ m. m < n0 → lf(m + 1) = nextl(m + 1, lf(m).last)) ⊦ ∃ lf. lf(0) = nextl(0, a) ∧ (∀ m. ¬ n0 < m → lf(m + 1) = nextl(m + 1, lf(m).last))

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2%succ: ⊦ m +1 = m + 1; from specification nat-basic2