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Proof step 39 from proof nextl-lemma (previous step)

∃ lf. lf(0) = nextl(0, a) ∧ (∀ m. m < n0 → lf(m + 1) = nextl(m + 1, lf(m).last)) ⊦ ∃ lf. lf(0) = nextl(0, a) ∧ (∀ m. ¬ n0 < m → lf(m + 1) = nextl(m + 1, lf(m).last))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
lf(0) = nextl(0, a), ∀ m. m < n0 → lf(m + 1) = nextl(m + 1, lf(m).last) ⊦ ∃ lf. lf(0) = nextl(0, a) ∧ (∀ m. ¬ n0 < m → lf(m + 1) = nextl(m + 1, lf(m).last))

Proof step 39 from proof nextl-lemma (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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