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Proof step 18 from proof nextl-nextj-lemma-butlast (previous step)

∀ m. lfgen(m)(0) = a ' ∧ iigen(m)(0) = n0 ∧ (∀ n. n ≤ m → lfgen(m)(n + 1) = nextl(iigen(m)(n), lfgen(m)(n).last) ∧ iigen(m)(n + 1) = nextj(iigen(m)(n), lfgen(m)(n).last)) ⊦ ∀ n. 0 ≤ n → lfgen(n)(0) = lfgen(0)(0) ∧ iigen(n)(0) = iigen(0)(0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
∀ m. lfgen(m)(0) = a ' ∧ iigen(m)(0) = n0 ∧ (∀ n. n ≤ m → lfgen(m)(n + 1) = nextl(iigen(m)(n), lfgen(m)(n).last) ∧ iigen(m)(n + 1) = nextj(iigen(m)(n), lfgen(m)(n).last)) ⊦ lfgen(n)(0) = lfgen(0)(0) ∧ iigen(n)(0) = iigen(0)(0)

Rule argument

Additional information

Used simplifier rules: lez: ⊦ 0 ≤ m; from specification nat