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Proof step 30 from proof nextl-nextj-lemma-butlast (previous step)

lfgen(m)(0) = a ', m0 < n, m0 + 1 < n, n1 ≤ m, ∀ n. n ≤ m → lfgen(m)(n + 1) = nextl(iigen(m)(n), lfgen(m)(n).last) ∧ iigen(m)(n + 1) = nextj(iigen(m)(n), lfgen(m)(n).last) ⊦ n = m0 + 1, n = 0, lfgen(n)(m0 + 1) = lfgen(m0 + 1)(m0 + 1) ∧ iigen(n)(m0 + 1) = iigen(m0 + 1)(m0 + 1), lfgen(m)(n1 + 1) = nextl(iigen(m)(n1), lfgen(m)(n1).last) ∧ iigen(m)(n1 + 1) = nextj(iigen(m)(n1), lfgen(m)(n1).last)

User applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n1 abort: F discard: T computed: T

Additional information

Used terms: n1