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Proof step 15 from proof weakmon-lem (previous step)

∀ n. ii(n) ≤ ii(n + 1) ⊦ ∃ m, n. (∀ m. ii(m) ≤ n) ∧ (∃ m. ii(m) = n), ∃ m. n ≤ ii(m), ∃ n0. ∀ m. n0 ≤ m → ii(m) = ii(n0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information