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Proof step 34 from proof weakmon-lem (previous step)

ii(m) < ii(m1), ∀ n. ii(n) ≤ ii(n + 1), ∀ n0, ii0. n0 < ii(m1) + 1 → (∀ n. ii0(n) ≤ ii0(n + 1)) → (∃ m. n0 ≤ ii0(m)) ∨ (∃ n. (∀ m. ii0(m) ≤ n) ∧ (∃ m. ii0(m) = n)) ⊦ ii(m1) = 0, ∃ n. (∀ m. ii(m) ≤ n) ∧ (∃ m. ii(m) = n), ∃ m. ii(m1) < ii(m), ∃ m. ii(m) = ii(m1)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 4 terms: m1

Additional information

Used terms: m1