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Proof step 1 from proof del-del-one (conclusion)

⊦ a ≠ b → (∅ ++ a) -- b = ∅ ++ a

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: del-in-03: ⊦ s -- a = s ↔ ¬ a ∈ s;%in-04: ⊦ a ∈ ∅ ++ b ↔ a = b; from specification infset-basic