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Proof step 14 from proof del-eq (previous step)

a2 ∈ s, a ∈ s0, a ∈ s, a0 ∈ s0, a1 ∈ s, ∀ a. a ∈ s ↔ a ∈ s0 ⊦ a2 ∈ s0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: a2

Additional information

Used terms: a2