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Proof step 12 from proof del-two (previous step)

a3 ∈ s, a2 ∈ s, a1 ∈ s, a0 ∈ s, a4 ∈ s, ∀ a4. a4 = b ∨ a4 = a ∨ ¬ a4 ∈ s ⊦ a2 = b, a3 = a, a1 = a, a3 = b

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: a3

Additional information

Used terms: a3