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Proof step 10 from proof int-ins (previous step)

a0 ∈ s0, a0 ∈ s, a1 ∈ s0, a2 ∈ s, ∀ a0. ¬ a0 ∈ s ∨ ¬ a0 ∈ s0 ⊦ a ∈ s

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: a0

Additional information

Used terms: a0