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Proof step 3 from proof une-01 (previous step)

∀ a. ¬ a ∈ s1 ∧ ¬ a ∈ s2 ⊦ (∀ a. ¬ a ∈ s1) ∧ (∀ a. ¬ a ∈ s2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ a. ¬ a ∈ s1 ∧ ¬ a ∈ s2 ⊦ ¬ a ∈ s1 ∧ ¬ a0 ∈ s2

Rule argument

Additional information