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Proof step 14 from proof unsub-union-01 (previous step)

a ∈ s2, a1 ∈ s2, a0 ∈ s2, ∀ a. a ∈ s1 ∨ a ∈ s2 → a ∈ s ⊦ a ∈ s1, a0 ∈ s

Heuristic quantifier closing applied rule all left

And obtained the following new goals

Proof step 15:
a ∈ s2, a1 ∈ s2, a0 ∈ s2, a ∈ s1 ∨ a ∈ s2 → a ∈ s, ∀ a. a ∈ s1 ∨ a ∈ s2 → a ∈ s ⊦ a ∈ s1, a0 ∈ s

Rule argument

pos: left 4 terms: a

Additional information

Used terms: a