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Proof step 2 from proof abs-21 (previous step)

⊦ i = j, abs(i) = abs(j) ↔ 0 = i + j

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 3:
i < 0 ⊦ i = j, abs(i) = abs(j) ↔ 0 = i + j
Proof step 5:
⊦ i < 0, i = j, abs(i) = abs(j) ↔ 0 = i + j

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0