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Proof step 3 from proof abs-le-succ (previous step)

⊦ i + 1 < 0, i < 0, i < abs(i + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ i < 0, i < abs(i + 1), i < ~1

Rule argument

Additional information

Used simplifier rules: numls-03: ⊦ i + (* j) < (* j0) ↔ i < j0 - j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2